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Applied Mathematics Chapter Vector  (Q&A)

 1. ____________ of the following is unit vector.

Answer : (`\frac{1}{\sqrt{2}}`,  `\frac{1}{\sqrt{2}}`)

 2. | 3i̅ - 4j̅ + 5k̅ | = ______.

   Answer : `5\sqrt2`

 3. Magnitude of  x̅ = 3i̅ + 2j̅ - 3k̅ is ______. 

   Answer : `\sqrt{22}`

 4. If x̅ = (2, 1) and y̅ = (-1, 3) then 2 x̅ + 3 y̅ = ____________.

   Answer : (1, 11)

 5. If  a̅ = (3, 7, 2) and  b̅ = 2i̅ + 5j̅ - 2k̅ then |a̅ +  b̅ | = __________.

   Answer : 13

 6. If  a̅ = (2, 1, -1) and  b̅ = (1, -3, 2) then |2a̅ -  3b̅ | = _______.

   Answer : `\sqrt{186}`

 7. If vectors  x̅ = (k, 2, -3) and y̅ = (`\sqrt{k}``\sqrt{13}`, 0) are of same magnitude then k =

   Answer : 0 OR 1 

 8.  If x(1, 2) + y(2, 1) = (3, 3) then x + y = ______.

   Answer : 2

 9. Direction angle of the vector x = j̅ + k̅ are _____.

   Answer : `\frac\pi2,\frac\pi4,\frac\pi4`

 10. If x̅ = (3, 2, 1) and y̅ = (1, 2, -1) then x̅ • y̅ = _______. 

   Answer : 6

 11. (3j - 2k + i) • ( 5k̅ + 3j̅ +2i̅ ) = ________.

   Answer : 1

 12. If x̅ = (secθ, tanθ, -1) and y̅ = (secθ, -tanθ, 1) then  x̅ • y̅ = _______.      

   Answer : 0

 13. The value of  i̅ • j̅ + j̅ • k̅ + k̅ • i̅  is __________.

   Answer : 0

 14. If (1, -3, 4) • (1, k, -4) then k = ________.

   Answer : 5 

 15. If x̅ = (k, 4, 2k) and y̅ = (2k, -1, k) then are mutually perpendicular then k = ___________.

   Answer : `\pm`1

 16.  If x̅ = i̅ + j̅ - k̅  and y̅ = 2j̅ - k̅ + i̅ then x̅ • y̅ = ________.

   Answer : 4

 17. If  x̅ = (1, 3, -2)  and y̅ = 4 i̅ - 2j̅ - k̅ then x̅ ^ y̅ = ________.

   Answer : 90°

 18. If x̅ = (1, 2, 1)  and y̅ = (1, -1, 1) then (x̅ + y̅) • (x̅ - y̅) =...

   Answer : 3

 19.  If |x̅| = 4 then x̅ • (5 • x̅ ) = ________.

   Answer : 80

 20. If x̅ × y̅ = (1, -2, -5) then  y̅ × x̅ = _______.

   Answer : y̅ × x̅ =  (-1, 2, 5)

 21.  x̅ × (x̅ - y̅) = ________.

   Answer : y̅ × x̅

 22.  If  x̅ = (1, 2, 3)  and y̅ = (-1, 3, 5) are given vector then x̅ ×  y̅ =...

   Answer : x̅ ×  y̅ = (1, -8, 5)

 23.  If  x̅ = (2, 2, -1)  and y̅ = (6, -3, 2) then  x̅ ×  y̅ =...

   Answer : x̅ ×  y̅ = (-1, 10, 18)

 24. A unit vector a long 3i + 4j is ______.

   Answer : 5

 25. ( i̅ - 2j̅ + 2k̅ ) = ________.

  Answer : 3

 26. If x(1, 1) + y(2, 1) = (3, 2) then (x, y) = _______.

   Answer : 1

 27. a̅ = - i̅ + 3j̅ , then  |a̅| = _____. 

   Answer : `\sqrt{10}`

 28. If  a̅ =  -2i + 3j + k ,  b̅ = 2i - 3j + 2k̅  then a̅ + b̅ = _______.

   Answer : (0, 0, 3)

 29. If  a̅ =  2i + j + k ,  b̅ = i - j + 3k̅  then a̅  b̅ = _______.

   Answer : 4

 30. a̅ =  2i + 3j - k ,  b̅ = 4i + 6j - 2k̅  then a̅ × b̅ = _______.

   Answer : 0

 31. a̅ =  i + j,  b̅ = j - k̅  then angle between a̅ and  b̅ = _______.

   Answer : 0

 32. (a̅ × • (b̅ × ) = _______.

   Answer : (a̅ × )²

 33. a̅  (a̅ × ) = _______.

   Answer : 0

 34. a̅ •  a̅ = ______.

   Answer : |a̅|²

 35.  •   = _______.

   Answer : 0

 36. If two forces (3i - j + 2k), (i + 3j -k) are applied on a particle , it's moves from (2i + 3j+ k ) to the point (5i + 2j +3k) then find the work done by three force. 

   Answer : W = 12 Units

 37. If 2i + 3j -k and pi - j + 3k are perpendicular each other then find the value of p. 

   Answer : P = 3

 38. If  a̅ = (p, 2, 1) and b̅ = (2, p, -4) are perpendicular each other then find the value of p. 

   Answer : P = 1

 39. If  a̅ = (2, 3, -1) and b̅ = (x, -1, 3) are perpendicular each other then find the value of x. 

   Answer : x = 0

 40. Find the unit vector perpendicular to the plane containing the vector a̅ =  i̅ - j̅ + k̅  and  = 2i̅ + 3j̅ - k̅.

   Answer : `\frac{1}{\sqrt{38}}`, (-2, 3, 8)



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